-2x^2-31x+10=-7x^2+4

Solution for -2x^2-31x+10=-7x^2+4 equation:

-2x^2-31x+10=-7x^2+4

We move all terms to the left:

-2x^2-31x+10-(-7x^2+4)=0

We get rid of parentheses

-2x^2+7x^2-31x-4+10=0

We add all the numbers together, and all the variables

5x^2-31x+6=0

a = 5; b = -31; c = +6;
Δ = b2-4ac
Δ = -312-4·5·6
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-29}{2*5}=\frac{2}{10}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+29}{2*5}=\frac{60}{10}
=6
$